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|Posté le: Jeu 9 Nov - 14:55 (2017) Sujet du message: solve for (x+4)2 =x(x-4) +5
|Hi, my name is Eddy. I need help in identifying what type of equation is this one and please, help solving it step by step, if it is possible.
(x+4)2 =x(x-4) +5
thanks a lot in advance
this is the part that i don't really understand so far
The x term is -16x. Take half its coefficient (-.
Square it (64) and add it to both sides
is this a constant.does it have to be done like that?. always?
Add '64' to each side of the equation.
-16x + 64 + x2 = 3 + 64
Reorder the terms:
64 + -16x + x2 = 3 + 64
Combine like terms: 3 + 64 = 67
64 + -16x + x2 = 67
Factor a perfect square on the left side: (don't get this part!!!) how do i factor a perfect square???
(x + -(x + - = 67
Calculate the square root of the right side: 8.185352772
I didn't find the right solution from the Internet.